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fix: use --template flag for server (#2643)

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# What does this PR do?

currently when a template is used, we still use `--config`.

`server.py` has a dedicated `--template` flag and logic, use that
instead

Signed-off-by: Charlie Doern <cdoern@redhat.com>
This commit is contained in:
Charlie Doern 2025-07-08 03:48:50 -04:00 • committed by GitHub
parent e9926564bd
commit 27b3cd570f
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2 changed files with 12 additions and 5 deletions
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13
llama_stack/cli/stack/run.py
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@ -155,8 +155,12 @@ class StackRun(Subcommand):
# func=<bound method StackRun._run_stack_run_cmd of <llama_stack.cli.stack.run.StackRun object at 0x10484b010>>
if callable(getattr(args, arg)):
continue
if arg == "config" and template_name:
server_args.config = str(config_file)
if arg == "config":
if template_name:
server_args.template = str(template_name)
else:
# Set the config file path
server_args.config = str(config_file)
else:
setattr(server_args, arg, getattr(args, arg))
@ -168,7 +172,10 @@ class StackRun(Subcommand):
run_args.extend([str(args.port)])
if config_file:
run_args.extend(["--config", str(config_file)])
if template_name:
run_args.extend(["--template", str(template_name)])
else:
run_args.extend(["--config", str(config_file)])
if args.env:
for env_var in args.env: