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chore: remove dead code

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# What does this PR do?


## Test Plan
This commit is contained in:
Eric Huang 2025-10-06 15:23:03 -07:00
parent 597d405e13
commit 2802974578
1 changed files with 0 additions and 33 deletions
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33
llama_stack/cli/stack/run.py
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@ -75,39 +75,6 @@ class StackRun(Subcommand):
help="Start the UI server",
)
def _resolve_config_and_distro(self, args: argparse.Namespace) -> tuple[Path | None, str | None]:
"""Resolve config file path and distribution name from args.config"""
from llama_stack.core.utils.config_dirs import DISTRIBS_BASE_DIR
if not args.config:
return None, None
config_file = Path(args.config)
has_yaml_suffix = args.config.endswith(".yaml")
distro_name = None
if not config_file.exists() and not has_yaml_suffix:
# check if this is a distribution
config_file = Path(REPO_ROOT) / "llama_stack" / "distributions" / args.config / "run.yaml"
if config_file.exists():
distro_name = args.config
if not config_file.exists() and not has_yaml_suffix:
# check if it's a build config saved to ~/.llama dir
config_file = Path(DISTRIBS_BASE_DIR / f"llamastack-{args.config}" / f"{args.config}-run.yaml")
if not config_file.exists():
self.parser.error(
f"File {str(config_file)} does not exist.\n\nPlease run `llama stack build` to generate (and optionally edit) a run.yaml file"
)
if not config_file.is_file():
self.parser.error(
f"Config file must be a valid file path, '{config_file}' is not a file: type={type(config_file)}"
)
return config_file, distro_name
def _run_stack_run_cmd(self, args: argparse.Namespace) -> None:
import yaml