fix: allow lookup of models registered at runtime

adds tests for ModelRegistryHelper to stabilize behavior
This commit is contained in:
Matthew Farrellee 2025-04-16 15:51:08 -04:00
parent e4d001c4e4
commit 9982aa64f0
3 changed files with 165 additions and 1 deletions

View file

@ -22,6 +22,27 @@ from llama_stack.schema_utils import json_schema_type
class ModelsProtocolPrivate(Protocol):
"""
Protocol for model management.
This allows users to register their preferred model identifiers.
Model registration requires -
- a provider, used to route the registration request
- a model identifier, user's intended name for the model during inference
- a provider model identifier, a model identifier supported by the provider
Providers will only accept registration for provider model ids they support.
Example,
register: provider x my-model-id x provider-model-id
-> Error if provider does not support provider-model-id
-> Error if my-model-id is already registered
-> Success if provider supports provider-model-id
inference: my-model-id x ...
-> Provider uses provider-model-id for inference
"""
async def register_model(self, model: Model) -> Model: ...
async def unregister_model(self, model_id: str) -> None: ...

View file

@ -59,6 +59,8 @@ def build_model_entry(provider_model_id: str, model_descriptor: str) -> Provider
class ModelRegistryHelper(ModelsProtocolPrivate):
def __init__(self, model_entries: List[ProviderModelEntry]):
self.supported_model_ids = {entry.provider_model_id for entry in model_entries}
self.alias_to_provider_id_map = {}
self.provider_id_to_llama_model_map = {}
for entry in model_entries:
@ -79,6 +81,16 @@ class ModelRegistryHelper(ModelsProtocolPrivate):
return self.provider_id_to_llama_model_map.get(provider_model_id, None)
async def register_model(self, model: Model) -> Model:
if model.provider_resource_id not in self.supported_model_ids:
raise ValueError(
f"Model id '{model.provider_resource_id}' is not supported. Supported ids are: {', '.join(self.supported_model_ids)}"
)
if model.model_id in self.alias_to_provider_id_map:
# be idemopotent
if model.provider_resource_id != self.alias_to_provider_id_map[model.model_id]:
raise ValueError(
f"Model id '{model.model_id}' is already registered. Please use a different id or unregister it first."
)
if model.model_type == ModelType.embedding:
# embedding models are always registered by their provider model id and does not need to be mapped to a llama model
provider_resource_id = model.provider_resource_id
@ -108,7 +120,12 @@ class ModelRegistryHelper(ModelsProtocolPrivate):
ALL_HUGGINGFACE_REPOS_TO_MODEL_DESCRIPTOR[llama_model]
)
self.alias_to_provider_id_map[model.model_id] = model.provider_resource_id
return model
async def unregister_model(self, model_id: str) -> None:
pass
if model_id not in self.alias_to_provider_id_map:
raise ValueError(f"Model id '{model_id}' is not registered.")
del self.alias_to_provider_id_map[model_id]

View file

@ -0,0 +1,126 @@
# Copyright (c) Meta Platforms, Inc. and affiliates.
# All rights reserved.
#
# This source code is licensed under the terms described in the LICENSE file in
# the root directory of this source tree.
#
# ModelRegistryHelper provides mixin functionality for registering and
# unregistering models. It maintains a mapping of model ID / aliases to
# provider model IDs.
#
# Test cases -
# - Looking up an alias that does not exist should return None.
# - Registering a model + provider ID should add the model to the registry. If provider ID is known.
# - Registering an existing model should return an error.
# - Unregistering a model should remove it from the registry.
# - Unregistering a model that does not exist should return an error.
# - Models can be registered during initialization or via register_model.
#
# Questions -
# - Should we be allowed to register models w/o provider model IDs? No.
# According to POST /v1/models, required params are
# - identifier
# - provider_resource_id
# - provider_id
# - type
# - metadata
# - model_type
#
# TODO: llama_model functionality
#
import pytest
from llama_stack.apis.models.models import Model
from llama_stack.providers.utils.inference.model_registry import ModelRegistryHelper, ProviderModelEntry
@pytest.fixture
def known_model() -> Model:
return Model(
provider_id="provider",
identifier="known-model",
provider_resource_id="known-provider-id",
)
@pytest.fixture
def known_provider_model(known_model: Model) -> ProviderModelEntry:
return ProviderModelEntry(
provider_model_id=known_model.provider_resource_id,
# aliases=[],
)
@pytest.fixture
def unknown_model() -> Model:
return Model(
provider_id="provider",
identifier="unknown-model",
provider_resource_id="unknown-provider-id",
)
@pytest.fixture
def helper(known_provider_model: ProviderModelEntry) -> ModelRegistryHelper:
return ModelRegistryHelper([known_provider_model])
@pytest.mark.asyncio
async def test_lookup_unknown_model(helper: ModelRegistryHelper, unknown_model: Model) -> None:
assert helper.get_provider_model_id(unknown_model.model_id) is None
@pytest.mark.asyncio
async def test_register_unknown_provider_model(helper: ModelRegistryHelper, unknown_model: Model) -> None:
with pytest.raises(ValueError):
await helper.register_model(unknown_model)
@pytest.mark.asyncio
async def test_register_model(helper: ModelRegistryHelper, known_model: Model) -> None:
assert helper.get_provider_model_id(known_model.model_id) is None
await helper.register_model(known_model)
assert helper.get_provider_model_id(known_model.model_id) == known_model.provider_resource_id
@pytest.mark.asyncio
async def test_register_model_existing(helper: ModelRegistryHelper, known_model: Model) -> None:
await helper.register_model(known_model)
with pytest.raises(ValueError):
await helper.register_model(known_model)
@pytest.mark.asyncio
async def test_unregister_model(helper: ModelRegistryHelper, known_model: Model) -> None:
await helper.register_model(known_model)
assert helper.get_provider_model_id(known_model.model_id) == known_model.provider_model_id
await helper.unregister_model(known_model.model_id)
assert helper.get_provider_model_id(known_model.model_id) is None
@pytest.mark.asyncio
async def test_unregister_unknown_model(helper: ModelRegistryHelper, unknown_model: Model) -> None:
with pytest.raises(ValueError):
await helper.unregister_model(unknown_model.model_id)
@pytest.mark.asyncio
async def test_register_model_during_init(helper: ModelRegistryHelper, known_model: Model) -> None:
assert helper.get_provider_model_id(known_model.provider_resource_id) == known_model.provider_model_id
@pytest.mark.asyncio
async def test_register_model_existing_from_init(helper: ModelRegistryHelper, known_model: Model) -> None:
assert helper.get_provider_model_id(known_model.provider_resource_id) == known_model.provider_model_id
with pytest.raises(ValueError):
known_model.identifier = known_model.provider_resource_id
await helper.register_model(known_model)
@pytest.mark.asyncio
async def test_unregister_model_during_init(helper: ModelRegistryHelper, known_model: Model) -> None:
assert helper.get_provider_model_id(known_model.provider_resource_id) == known_model.provider_model_id
await helper.unregister_model(known_model.provider_resource_id)
assert helper.get_provider_model_id(known_model.provider_resource_id) is None